Css only type grinding

/* https://www.bitovi.com/blog/css-only-type-grinding-casting-tokens-into-useful-values */

@property --variant {
  syntax: "primary|secondary|success|error";
  initial-value: primary;
  inherits: true;
}

@property --_v-primary-else-0 {
  syntax: "primary|<integer>"; initial-value: 0; inherits: true;
}


@property --_v-primary-bit {
  syntax: "<integer>"; initial-value: 1; inherits: true;
}


.element {
  --variant: primary;
  --_v-primary-else-0: var(--variant);
  --_v-primary-bit: var(--_v-pr

3539. Find Sum of Array Product of Magical Sequences

You are given two integers, m and k, and an integer array nums. A sequence of integers seq is called magical if: seq has a size of m. 0 <= seq[i] < nums.length The binary representation of 2seq[0] + 2seq[1] + ... + 2seq[m - 1] has k set bits. The array product of this sequence is defined as prod(seq) = (nums[seq[0]] * nums[seq[1]] * ... * nums[seq[m - 1]]). Return the sum of the array products for all valid magical sequences. Since the answer may be large, return it modulo 109 + 7. A set bit refers to a bit in the binary representation of a number that has a value of 1.
/**
 * @param {number} m
 * @param {number} k
 * @param {number[]} nums
 * @return {number}
 */
var magicalSum = function(m, k, nums) {
    const MOD = BigInt(1e9 + 7); // Modulo for large number arithmetic
    const n = nums.length;

    // Precompute binomial coefficients: comp[i][j] = C(i, j)
    const comp = Array.from({ length: m + 1 }, () => Array(m + 1).fill(0n));
    for (let i = 0; i <= m; i++) {
        comp[i][0] = 1n;
        comp[i][i] = 1n;
        for (let j = 1; j < i; j++) {
   

C1 U6

persecute vs prosecute
lessen vs diminish
make out capital of sth - only about money?
paramount vs the most - which context
a body of - The committee is made up of a body of experts in the field.

3186. Maximum Total Damage With Spell Casting

A magician has various spells. You are given an array power, where each element represents the damage of a spell. Multiple spells can have the same damage value. It is a known fact that if a magician decides to cast a spell with a damage of power[i], they cannot cast any spell with a damage of power[i] - 2, power[i] - 1, power[i] + 1, or power[i] + 2. Each spell can be cast only once. Return the maximum possible total damage that a magician can cast.
/**
 * @param {number[]} power
 * @return {number}
 */
var maximumTotalDamage = function(power) {
    // Step 1: Count how many times each damage value appears
    const count = new Map();
    for (const dmg of power) {
        count.set(dmg, (count.get(dmg) || 0) + 1);
    }

    // Step 2: Sort unique damage values in ascending order
    const unique = Array.from(count.keys()).sort((a, b) => a - b);
    const n = unique.length;

    // Edge case: only one unique damage value
    if (n === 1) {

Laravel VISA - probar email

<?php

/**
 * Archivo de prueba para enviar un email usando DocumentMail
 * 
 * Este archivo es SOLO para pruebas y NO debe usarse en producción.
 * No modifica ningún archivo existente del proyecto.
 * 
 * Para ejecutar: php test-document-mail.php
 */

require_once __DIR__ . '/vendor/autoload.php';

use Illuminate\Foundation\Application;
use Illuminate\Contracts\Console\Kernel;
use App\Mail\DocumentMail;
use Illuminate\Support\Facades\Mail;

// Inicializar Laravel
$app = requ

javascript - selector de birth date

const birthDatePicker = new easepick.create({
    ...defaultPickerConfig,
    element: "#birth_date",
    AmpPlugin: {
        dropdown: {
            maxYear: new Date().getFullYear(),
            minYear: 1930,
            months: true,
            years: true,
        },
        resetButton: true,
        darkMode: false
    },
    LockPlugin: {
        minDate: null,
        maxDate: todayInAruba,
        filter(date, picked) {
            return date.getTime() > todayInArub

3147. Taking Maximum Energy From the Mystic Dungeon

In a mystic dungeon, n magicians are standing in a line. Each magician has an attribute that gives you energy. Some magicians can give you negative energy, which means taking energy from you. You have been cursed in such a way that after absorbing energy from magician i, you will be instantly transported to magician (i + k). This process will be repeated until you reach the magician where (i + k) does not exist. In other words, you will choose a starting point and then teleport with k jumps until you reach the end of the magicians' sequence, absorbing all the energy during the journey. You are given an array energy and an integer k. Return the maximum possible energy you can gain. Note that when you are reach a magician, you must take energy from them, whether it is negative or positive energy.
/**
 * @param {number[]} energy
 * @param {number} k
 * @return {number}
 */
var maximumEnergy = function(energy, k) {
    // Initialize the answer to a very low number to ensure any valid energy path will be higher
    let ans = -1e99;

    // Try starting from each index i in the range [0, k)
    // These are the only starting points that can reach the end via i + k jumps
    for (let i = 0; i < k; i++) {
        // Start with the energy at index i
        let cur = energy[i];

        // Set 

Simple tabs

document.addEventListener("DOMContentLoaded", function() {
  var customTabsTitles = document.querySelectorAll('.product-custom-tabs-header-item');
  if (customTabsTitles.length) {
    customTabsTitles.forEach(function(item) {
      item.addEventListener("click", function() {
        var customTabsBody = this.closest('.product-custom-tabs').querySelectorAll('.product-custom-tabs-body-item');
        var currentId = this.getAttribute('data-id'); 
        customTabsTitles.forEach(function(el

📒 Notebook LM - Sourcing Liens

# 20 High-Quality Educational Resources: VS Code and Jupyter for Programming Beginners

This curated collection provides approximately 20 premium educational resources specifically selected for business users new to programming. These materials cover VS Code features, Jupyter notebook fundamentals, and their integration—ideal for generating training content with Notebook LM.

## VS Code Fundamentals (6 resources)

### 1. Tutorial: Get started with Visual Studio Code
**URL:** https://code.

📒 Notebook LM - Video Example

# TARGET AUDIENCE
Data professionals with a few coding experience, including data analysts, product owners, project leaders, managers.

# GOAL
Build foundational understanding of VS Code and Jupyter environment, essentially in Python to enable ease in practical use within a few days

# INCLUDE
- "What are VS Code and Jupyter environment?" in simplest possible terms (use analogies)
- Why VS Code and Jupyter environment were created (the problem it solves)
- The ONE most important thing t

📒 Notebook LM - Video Template

# AUDIENCE

# GOAL

# INCLUDE

# EXCLUDE

# TONE

# STRUCTURE

# VISUAL STYLE

# PEDAGOGICAL PRINCIPLES

📒 Notebook LM - Flashcards Template

# LANGUAGE
French (MANDATORY, translate if necessary).

# INCLUDE
Focus on questions about {{TOPIC_1}}.

# EXCLUDE
Limit questions about {{TOPIC_2}} to {{LIMIT}}.

Python venv

python -m venv venv
source venv/bin/activate

3494. Find the Minimum Amount of Time to Brew Potions

You are given two integer arrays, skill and mana, of length n and m, respectively. In a laboratory, n wizards must brew m potions in order. Each potion has a mana capacity mana[j] and must pass through all the wizards sequentially to be brewed properly. The time taken by the ith wizard on the jth potion is timeij = skill[i] * mana[j]. Since the brewing process is delicate, a potion must be passed to the next wizard immediately after the current wizard completes their work. This means the timing must be synchronized so that each wizard begins working on a potion exactly when it arrives. ​ Return the minimum amount of time required for the potions to be brewed properly.
/**
 * @param {number[]} skill
 * @param {number[]} mana
 * @return {number}
 */
var minTime = function(skill, mana) {
    let m = mana.length;       // Number of potions
    let n = skill.length;      // Number of wizards

    // done[i] represents the time when wizard i is ready to start the next potion
    // We use n+1 to simplify indexing (done[n] will hold the final result)
    let done = new Array(n + 1).fill(0);

    // Loop through each potion in order
    for (let j = 0; j < m; j++) {

IOS

//after clonning backend ios project:

swift package resolve