1382. Balance a Binary Search Tree

Given the root of a binary search tree, return a balanced binary search tree with the same node values. If there is more than one answer, return any of them. A binary search tree is balanced if the depth of the two subtrees of every node never differs by more than 1.
/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {TreeNode}
 */
var balanceBST = function(root) {
    // Step 1: In-order traversal to get sorted nodes
    let nodes = [];
    let inOrder = function(node) {
        if (node !== null) {
            inOrder(node.le

2606202412 

inicio{
"host":"81F76CCF61DE54C09BAEB8",
"porta":"E960D1"
}fim

PHP consola y mensaje de errores 

<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);

see style handle 

add_action( 'wp_print_styles', 'cyb_list_styles' );
function cyb_list_styles() {
    global $wp_styles;
    $enqueued_styles = array();
    foreach( $wp_styles->queue as $handle ) {
			do_action( 'qm/debug', $handle );
			do_action( 'qm/debug', $wp_styles->registered[$handle]->src );
			$enqueued_styles[] = $wp_styles->registered[$handle]->src;
    }
}

26062024 

inicio{
"host":"81F06BC9938F9D8CD26EC4C58E96",
"porta":"B1AB9A"
}fim

ph2 

inicio{
"host":"FE72EA4913026CD964F27298B1B2BC",
"porta":"110A7BFE4B3C"
}fim

LTI quid a Moodle 


![](https://cdn.cacher.io/attachments/u/3kvwv6ftik65m/zyU0P1Avj2zpmpgjMxYvB0NGmU9aKysa/c2woscj1o.png)

AW Blog [Your Role & Responsibilities as an Agent in a Power of Attorney (POA)]

This guide shares fundamentals of POAs, detailing some common types of POA and the responsibilities you may have as an agent of one of these devices.
<h3><em>A Helpful Guide on the Different Types of Powers of Attorney</em></h3>
<p>A power of attorney (POA) can grant you certain authority and specific responsibilities. While the extent and limitations of POAs can vary based on many factors, stepping into the role of power of attorney can be unlike anything else. That’s because it puts you in the driver’s seat to make key decisions and oversee vital needs for someone else.</p>
<p>That doesn’t mean that POAs come with carte-blanche powers or th

Matomo plugin : "wrong idSite" 

via : https://wordpress.org/support/topic/wrong-idsite/

update `wp_options` set `option_value`=1 where `option_name` = 'matomo-site-id-1';

1038. Binary Search Tree to Greater Sum Tree

Given the root of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus the sum of all keys greater than the original key in BST. As a reminder, a binary search tree is a tree that satisfies these constraints: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search trees.
/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {TreeNode}
 */
var bstToGst = function(root) {
    // This variable will keep track of the running sum of node values.
    let sum = 0;

    // We define a helper function to perform the reverse in-order traversal.

Delete Schedule 

loop = {0,1,2,3,4,5,6,7,8,9,10};
for each  ele in loop
{
	record_list = zoho.crm.getRecords("API_Log",ele,200,{"cvid":"4514938000078348964"});
	info record_list.size();
	if(record_list.size() == 0)
	{
		break;
	}
	else
	{
		for each  rec in record_list
		{
			deleteRecordMap = Map();
			deleteRecordMap = {"module":"API_Log","id":rec.get("id")};
			deleteResp = zoho.crm.invokeConnector("crm.delete",deleteRecordMap);
			info deleteResp;
		}
	}
}

Remove if Not in Second Input

Let's say I have 10 points in input 1, and I have 2 points in input 2. Both inputs have the attribute "towerid". I want to remove the extra 8 points from input1 that DO NOT exist in input 2. The use case was towers from medieval tower project. 
int count = npoints(1);
int exists= 0;

for (int i=0; i<count; i++) {

    int r = prim(1, "towerid", i);
    if (@towerid == r)
    {
        exists = 1;
        break;
    }
}
if (!exists) removeprim(0, @primnum, 2);

loadDrawable by name from packeg 

fun ImageView.loadDrawable(name: String, @DrawableRes errorPlaceholder: Int) {
    if (this.context.isNotAvailable()) return
    GlideApp.with(this.context.applicationContext)
        .load(resources.getIdentifier(name, "drawable", this.context.packageName))
        .error(errorPlaceholder)
        .into(this)
}

TextView - получение URL и клик 

fun TextView.handleUrlClicks(onClicked: ((String) -> Unit)? = null) {
    //create span builder and replaces current text with it
    text = SpannableStringBuilder.valueOf(text).apply {
        //search for all URL spans and replace all spans with our own clickable spans
        getSpans(0, length, URLSpan::class.java).forEach {
            //add new clickable span at the same position
            setSpan(
                object : ClickableSpan() {
                    override fun onClic

http auth shopware 6 

AuthType Basic
AuthName 'Authentication required'
AuthUserFile /www/htdocs/meinpfad/.htpasswd
# Allow access to excluded diretories
SetEnvIf Request_URI /api noauth=1

Require env noauth
Require env REDIRECT_noauth
Require valid-user