class Solution(object):
def missingNumber(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
x = 0
for i in range(len(nums)+1):
x ^= i
for i in nums:
x ^= i
return x
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
For example,
Given nums = [0, 1, 3]
return 2
.
Note: Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?