moonlightshadow123
6/19/2017 - 9:39 AM

54. Spiral Matrix

  1. Spiral Matrix
n_m_row_col.py
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class Solution(object):
    def spiralOrder(self, matrix):
        """
        :type matrix: List[List[int]]
        :rtype: List[int]
        """
        if matrix == []:
            return []
        elements = []
        m = len(matrix)
        n = len(matrix[0])
        row = 0
        col = -1
        while True:
            for i in range(n):
                col += 1
                elements.append(matrix[row][col])
            m -= 1
            if m == 0:
                break
            #####################################
            for i in range(m):
                row += 1
                elements.append(matrix[row][col])
            n -= 1
            if n == 0:
                break
            ####################################
            for i in range(n):
                col -= 1
                elements.append(matrix[row][col])
            m -= 1
            if m == 0:
                break
            ####################################
            for i in range(m):
                row -= 1
                elements.append(matrix[row][col])
            n -= 1
            if n == 0:
                break
        return elements
54-Spiral-Matrix.md
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https://leetcode.com/problems/spiral-matrix/#/description

Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.

For example, Given the following matrix:

[
 [ 1, 2, 3 ],
 [ 4, 5, 6 ],
 [ 7, 8, 9 ]
]

You should return [1,2,3,6,9,8,7,4,5].