class Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
recd = [-1] * 256
start = 0; max_len = 0
for end in range(len(s)):
if recd[ord(s[end])] >= start:
start = recd[ord(s[end])] + 1
recd[ord(s[end])] = end
max_len = max(end - start + 1, max_len)
return max_lenclass Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
recd = [False] * 256
start = 0; max_len = 0
for end in range(len(s)):
if recd[ord(s[end])] == True:
while s[start] != s[end]:
recd[ord(s[start])] = False
start += 1
start += 1
recd[ord(s[end])] = True
max_len = max(end - start + 1, max_len)
return max_lenhttps://leetcode.com/problems/longest-substring-without-repeating-characters/#/description
Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb", the answer is "abc", which the length is 3.
Given "bbbbb", the answer is "b", with the length of 1.
Given "pwwkew", the answer is "wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.