puiu91
10/8/2015 - 12:56 PM

jQuery Ajax

jQuery Ajax


var requestAJAX = jQuery.ajax({
    method: 'POST',
    url: 'data-export.php',
    dataType: 'html',
    data: { nameOfArrayPassedToServer : arrayNameInJS }
});

requestAJAX.done(function(response) {
    console.log(response);

    for (var i = 0; i < response.length; i++)
        jQuery( '#target' ).append(response[i]);

    progressSpinner('hide');
});

requestAJAX.fail(function(response){
    console.log('ajax failed');
    progressSpinner('hide');
});