moonlightshadow123
6/22/2017 - 4:12 AM

107. Binary Tree Level Order Traversal II

  1. Binary Tree Level Order Traversal II
# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def levelOrderBottom(self, root):
        """
        :type root: TreeNode
        :rtype: List[List[int]]
        """
        if root == None:
            return []
        self.res = []
        self.DFS(root, 1)
        return self.res[::-1]
    def DFS(self, node, level):
        if node == None:
            return
        if len(self.res) < level:
            self.res.append([])
        self.res[level-1].append(node.val)
        self.DFS(node.left, level+1)
        self.DFS(node.right, level+1)

https://leetcode.com/problems/binary-tree-level-order-traversal-ii/#/description

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).

For example: Given binary tree [3,9,20,null,null,15,7],

    3
   / \
  9  20
    /  \
   15   7

return its bottom-up level order traversal as:

[
  [15,7],
  [9,20],
  [3]
]