# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def isSymmetric(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
if root == None:
return True
return self.check(root.left, root.right)
def check(self, node1, node2):
if node1 == None and node2 == None:
return True
elif node1 == None or node2 == None:
return False
else:
cond1 = node1.val == node2.val
cond2 = self.check(node1.right, node2.left)
cond3 = self.check(node1.left, node2.right)
return cond1 and cond2 and cond3
https://leetcode.com/problems/symmetric-tree/#/description
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree [1,2,2,3,4,4,3]
is symmetric:
1
/ \
2 2
/ \ / \
3 4 4 3
But the following [1,2,2,null,3,null,3]
is not:
1
/ \
2 2
\ \
3 3