CodyKochmann
1/20/2017 - 7:47 PM
returns the index of a list if it is a sublist of another list in python
returns the index of a list if it is a sublist of another list in python
def find_sublist(l1,l2,depth=0):
""" returns the index of a list in another list
by: Cody Kochmann """
if not len(l1) or not len(l2): return -1
return depth if l2[:len(l1)] == l1 else find_sublist(l1, l2[1:], depth+1)