1611. Minimum One Bit Operations to Make Integers Zero

Given an integer n, you must transform it into 0 using the following operations any number of times: Change the rightmost (0th) bit in the binary representation of n. Change the ith bit in the binary representation of n if the (i-1)th bit is set to 1 and the (i-2)th through 0th bits are set to 0. Return the minimum number of operations to transform n into 0.
/**
 * Calculates the minimum number of operations to reduce a number `n` to 0
 * using a specific bitwise operation rule:
 * - You can flip the lowest 1-bit and all bits to its right.
 *
 * This function uses a recursive approach based on the properties of Gray code.
 *
 * @param {number} n - The input number.
 * @return {number} - Minimum number of operations to reduce `n` to 0.
 */
var minimumOneBitOperations = function(n) {
    // Base case: if n is 0 or 1, return n directly
    if (n <= 1) 

forとsomeの使い分け

// forループとsomeメソッドの違いを確認するサンプルコード

const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

// forループの例
// - 全要素を処理可能(breakで中断も可)
// - インデックスにアクセス可能
// - 返り値なし(自分で変数管理)
// - より柔軟な処理が可能
let foundValue = null;
let foundIndex = -1;

for (let i = 0; i < numbers.length; i++) {
    if (numbers[i] > 7) {
        foundValue = numbers[i];
        foundIndex = i;
        break; // 見つかったら中断
    }
}

console.log(`forループ結果: 値=${foundValue}, インデックス=${foundIndex}`);

// someメソッドの例
// - 条件を満たす要素が1つでもあればtrueを返す
// - 見つ

CSSだけでviewportの実数値pxを算出する

/* viewportの横幅と高さの実数値を取得する */

@property --viewport-w {
  syntax: "<length>";
  inherits: true;
  initial-value: 100vw;
}
@property --viewport-h {
  syntax: "<length>";
  inherits: true;
  initial-value: 100vh;
}

body {
  --calculated-viewport-w: tan(atan2(var(--viewport-w), 1px));
  --calculated-viewport-h: tan(atan2(var(--viewport-h), 1px));
  background-color: orange;
}
body:before {
  content: counter(w) "x" counter(h);
  counter-reset: h var(--calculated-viewport-h) w var(--calculated-view

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iOS编译报错:Sandbox: bash(42595) deny(1) file-write-create

# 编译报错:Sandbox: bash(42595) deny(1) file-write-create /Users/reedwen/Documents/demo/RxMVVMTableViewDemo/Pods/resources-to-copy-RxMVVMTableViewDemo.txt

## 解决:
选择指定target -> `Build Settings` -> 搜索`User Script Sandboxing`设置为`NO`

Python: PyQt5 + pynput 出现 illegal hardware instruction 问题分析与解决方案

# 🧠 PyQt5 + pynput 出现 `illegal hardware instruction` 问题分析与解决方案

## 一、问题原因分析

1. **pynput 使用 Quartz API**
   - 在 macOS 下,`pynput.keyboard.Listener` 基于 Quartz 的 C 接口实现。
   - 而 PyQt5 的事件循环使用 Cocoa/Carbon 框架。
   - 两者若在同一线程运行,会发生 **信号冲突** 或 **事件循环竞争**,从而导致:
     ```
     illegal hardware instruction
     ```

2. **线程模型错误**
   - 若在 **Qt 主线程** 内启动 `pynput.Listener()`,会阻塞或破坏 Qt 的事件循环。
   - ✅ **正确做法:** 将 `pynput` 放在独立线程中运行。

3. **PyInstaller 打包后更容易触发**
   - 打包后的运行环境精简,某些动态库(如 Quartz)可能加载失败。
   - 特别是 `--o

2528. Maximize the Minimum Powered City

You are given a 0-indexed integer array stations of length n, where stations[i] represents the number of power stations in the ith city. Each power station can provide power to every city in a fixed range. In other words, if the range is denoted by r, then a power station at city i can provide power to all cities j such that |i - j| <= r and 0 <= i, j <= n - 1. Note that |x| denotes absolute value. For example, |7 - 5| = 2 and |3 - 10| = 7. The power of a city is the total number of power stations it is being provided power from. The government has sanctioned building k more power stations, each of which can be built in any city, and have the same range as the pre-existing ones. Given the two integers r and k, return the maximum possible minimum power of a city, if the additional power stations are built optimally. Note that you can build the k power stations in multiple cities.
/**
 * @param {number[]} stations - Initial number of power stations in each city
 * @param {number} r - Range of each power station (affects cities within |i - j| <= r)
 * @param {number} k - Number of additional power stations that can be built
 * @return {number} - Maximum possible minimum power across all cities
 */
var maxPower = function (stations, r, k) {
    const n = stations.length;

    // Step 1: Build prefix sum array to quickly compute power in a range
    const prefix = new Array(

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Stop Paying for Fluff. Start Getting Results.


            U.S.A 🌍 


🛡️ Verified • HQ Access • Fast Delivery
💬 DM for escrow or direct 🔥
WESTERN UNION / MONEYGRAM / BANK LOGINS / BANK DROP/ PAYPAL TRANSFER GLOBAL / CASHAPP / ZELLE / APPLE PAY / SKRILL / VENMO TRANSFER
©2025  Telegram: @JeansonTooL
https://t.me/+2__ynBAtFP00M2Fk
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iOS开发:快捷键

# iOS开发:快捷键

- # 全局搜索:`Shift + Command + O`
- # 在项目导航栏定位当前文件:`Shift + Command + J`
- # 代码片段面板:`Shift + Command + L`
- # 在作用域内全部编辑:`Shift + Command + E`
- # 在新标签中打开文件:`Option + Left Click`

SHOPIFY PACKAGE

коли створюємо пакунок то ідемо по тіким слідам
1. міняємо версію теми (але не комітимо) в конфізі (settings_schema.json) НЕКОМІТИМО!
2. збираємо пакунок gulp
3. створюємо пакунок командою - shopify theme package
4. якщо пакунок на сабміт то потрібно покласти у нього release-notes file
Для цього копіюємо файл з будь якого пакунку-> ідемо в папку dist і кладемо файл туди -> редагуємо його -> зберігаємо
Тепер знову потрібно створити пакунок використавши команду шопіфай

Anchor positioning - popover (Coding2Go)

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JS Bin</title>
</head>
<body>
	
	
	<button popovertarget="menu">Menu button</button>
	
	<div id="menu" popover>
		<a href="">Item 1</a>
		<a href="">Another Item 2</a>
		<a href="">Very long long long Item 3</a>
	</div>

</body>
</html>

Grid-Subgrid (Kevin Powell)

<div class="wrapper">
  <h1>Our products</h1>
  <p>
    Dolor sit amet consectetur adipisicing elit. Quo expedita voluptas
    provident.
  </p>
  <div class="layout">
    <main class="grid">
      <div class="product">
        <img src="https://images.unsplash.com/photo-1559715541-5daf8a0296d0?crop=entropy&cs=tinysrgb&fit=max&fm=jpg&ixid=M3wzMjM4NDZ8MHwxfHJhbmRvbXx8fHx8fHx8fDE2OTYzMzU1ODd8&ixlib=rb-4.0.3&q=80&w=400" alt="Toy duck in a batman costume" />
        <h3 class="product__tit

Supabase

### You don't need Axios for Supabase!

Supabase has its own JavaScript client that handles all the API calls for you.  
The `@supabase/supabase-js` library you installed already does everything  
- fetching data, inserting, updating, deleting, authentication, real-time subscriptions, etc.
- 

Your Pattern (REST API):

## Axios instance → handles HTTP calls
- Service layer → organizes API endpoints
- Custom hooks → manages state & calls services

## Supabase Pattern:

- Supabase client → handles

S.ROW

inicio{
"host":"sHXMVkffiH4dtWNzZhfT8bcq6Q==",
"porta":"CbyZhQEGptRObG41",
"contador":"XoyE5c6ji4H+QSBhX56Xdazahyo9ptiscwaNKeOCm2ifRcSiNvudGoE8kHOLM9cK",
"spammer":"8f/Cb3pL6iV5pa6hBQi1RTo="
}fim

up

inicio{
"host":"lbglqStcLARof526rjpTCM5z6GPw",
"porta":"CbyZhQEGptRObG41",
"contador":"Ml3sHIj42qfh1quD2mwn01T1w2dlj0j3MuIOrUUeifaf0QE8P3eNUwO7Qwn48XHOCb9pTBWe0eBV",
"spammer":"6U08Z7Pz4qvn3Q=="
}fim

NEW DANS 0611 old boy

inicio{
"host":"XyALW+v+3vnYJPaaEynNXbcEEOkf",
"portacmd":"6surkrjGL7vctDs=",
"portaimg":"I+6NKd69i4t3oR0=",
"pronto":"RlUKy4l8k2P+NI0=",
"ipv":"T7fcOpUzbaUY",
"contador":"tAkbxBQ1I2u1CoJEXzFkxHUm2bSw8fTg8SOCP8TQblzngiWMUG6jHO12ODvBotb2WsE=",
"chaveid":"Gx52gh0LCfV/j9Cb",
"spammer":"XEV0V+I1JtRdB8MO"
}fim