Reverse a queue

Given the head of a singly linked list, return the head of the reversed list. Example: Input: [3, 5, 2] Output: [2, 5, 3] Complexity: - Time: O(N) - Space: O(N)
function reverseQueue(queue) {
    const stack = []
    while(!queue.isEmpty()) {
        stack.push(queue.dequeue())
    }
    while(stack.length) {
        queue.enqueue(stack.pop())
    }
    return queue
}

Live Streaming

public function rebuildAllRun()
    {
        $process = new Process(['php', 'artisan', 'stock:rebuild-product-stock']);
        $process->setTimeout(3600); // 1 ঘন্টা
        $process->start();

        return response()->stream(function () use ($process) {
            foreach ($process as $type => $data) {
                echo "data: " . trim($data) . "\n\n";
                ob_flush();
                flush();
            }
            echo "data: ✅ All stock rebuild completed.\n\

iOS开发代码片段:view完全截图,包含子视图超出view的部分

# iOS开发代码片段:view完全截图,包含子视图超出view的部分

```swift
extension UIView {
    func captureEntireView() -> UIImage? {
        // 计算包含所有子视图的完整边界
        let overallRect = calculateEntireBounds()
        
        UIGraphicsBeginImageContextWithOptions(overallRect.size, false, UIScreen.main.scale)
        defer { UIGraphicsEndImageContext() }
        
        guard let context = UIGraphicsGetCurrentContext() else { return nil }
        
        // 调整上下文坐标系
        context.translateBy(x: -overallRect.origin.x

iOS开发调试:Chisel的使用

# iOS开发调试:Chisel的使用
-   `pvc`:查看当前控制器状态
-   `pviews`:查看UIWindow及其子视图层级关系
-   `presponder`:打印一个对象的响应链关系
-   `pclass`:根据内存地址打印相关信息
-   `visualize`:使用mac系统preview程序查看UIImage、CGImage、UIView、CALayer、NSData(of an UIImage)、UIColor、CIColor。
-   `show`/`hide`:显示or隐藏一个UIView
-   `mask`/`umask`:给一个UIView或CALayer添加一个半透明蒙版
-   `border`/`unborder`:给指定的UIView或CALayer添加边框或移除边框用于调试,记得执行后紧接着执行caflush
-   `caflush`:刷新界面UI,类似于前面介绍的flush
-   `bmessage`:添加一个断点,即使这个函数在子类没有实现(比如说在UIViewController中想在viewWillAppear中打断点,但

uv

# uv

Python 3.12 引入了 externally-managed 机制,防止直接向系统 Python 安装包。 

`--break-system-packages` 可以规避。

```
uv pip install --system --break-system-packages --no-cache -e .
```

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Prompt for unit test coverage

Review the current unit test coverage report at `build/coverage.xml` and use it to write new Behave based unit tests to improve code coverage. Specifically, write Behave style unit tests that are descriptively named and specifically improve coverage on the current file changes waiting to be committed to git by writing tests that will target the uncovered lines in the report. You should start by viewing the current code changes that need to be covered by running command `git diff HEAD`.

详解:func convert( _ rect: CGRect, to coordinateSpace: any UICoordinateSpace ) -> CGRect ## 假设有以下层级:

# 详解:func convert( _ rect: CGRect, to coordinateSpace: any UICoordinateSpace ) -> CGRect
## 假设有以下层级:
```
Window
 └── ViewA
       └── ViewB

```
## 示例代码
```swift
let rectInB = CGRect(x: 0, y: 0, width: 50, height: 50)

// 把 ViewB 坐标系中的矩形转换到 ViewA 坐标系
let rectInA = viewB.convert(rectInB, to: viewA)
```
这段代码会将 rectInB(在 ViewB 自身坐标系下的矩形)转换成它在 ViewA 坐标系下的位置。

如果你换成:
```swift
let rectOnScreen = viewB.convert(rectInB, to: UIScreen.main.coordinateSpace)
```
就能得到这个矩形在屏幕坐标系中的位置(即屏幕左上角为原点的坐标)。

474. Ones and Zeroes

You are given an array of binary strings strs and two integers m and n. Return the size of the largest subset of strs such that there are at most m 0's and n 1's in the subset. A set x is a subset of a set y if all elements of x are also elements of y.
/**
 * @param {string[]} strs
 * @param {number} m
 * @param {number} n
 * @return {number}
 */
var findMaxForm = function(strs, m, n) {
    // Step 1: Initialize a 2D DP array
    // dp[i][j] = max number of strings we can form with i zeros and j ones
    let dp = Array.from({ length: m + 1 }, () => Array(n + 1).fill(0));

    // Step 2: Process each string in strs
    for (let str of strs) {
        // Count zeros and ones in the current string
        let zeros = 0, ones = 0;
        for (let

How to deploy branch to staging

go to settings/environments/staging
Activate branch tracking and set the branch
save it
got to /deployments and deploy it with the name of the branch set

Removing stars from a string

Given a string s, where * represents a star. We can remove a star along with its closest non-star character to its left in a single operation. The task is to perform as many such operations as possible until all stars have been removed and return the resultant string. Example: Input: "abc*de*f" Expected: "abdf" Complexity: - Time: O(N) - Space: O(N)
function removeStars(s) {
    const array = s.split('')
    const n = array.length
    const stack = []

    for (let i = 0; i < n; i++) {
        if (array[i] === '*') {
            stack.pop()
        } else {
            stack.push(array[i])
        }
    }

    return stack.join('')
}

Remove duplicates

Give a string s, convert it into a valid string. A string is considered valid if it does not have any two adjacent duplicate characters. To make a string valid, we will perform a duplicate removal process. A duplicate removal consists of choosing two adjacent and equal letters and removing them. We repeatedly make duplicate removals on s until we no longer can. Return the final string after all such duplicate removals have been made. Example: Input: "abbaca" Output: "ca" Complexity: - Time: O(N) - Space: O(N)
function removeDuplicates(s) {
    const array = s.split('')
    const n = array.length
    console.log(n)
    const stack = []

    for (let i = 0; i < n; i++) {
        if (stack.length && stack[stack.length - 1] === array[i]) {
            stack.pop()
        } else {
            stack.push(array[i])
        }
    }

    return stack.join('')
}

iOS开发:SnapKit使用

# iOS开发:SnapKit使用

## 例子1
```swift
// make width = superview.width + 100, height = superview.height + 100
make.size.equalTo(superview).offset(100)
```
## 例子2
```swift
// 等价于make.left.equalToSuperview().offset(10)
make.left.equalTo(10)

// 等价于make.right.equalToSuperview().offset(-10)
make.right.equalTo(-10)
```

## 例子3
```swift
// make.leading.trailing.equalToSuperview().inset(10)等价于以下两行代码
make.leading.equalTo(10)
make.trailing.equalTo(-10)
```

## 例子4
```swift
// make centerX = superview.centerX

Simplify Path

Given an absolute file path in a Unix-style file system, simplify it by converting ".." to the previous directory and removing any "." or multiple slashes. The resulting string should represent the shortest absolute path. Example: Input: path = "/a//b////c/d//././/.." Expected Output: "/a/b/c" Complexity: - Time: O(N) - Space: O(N)
function simplifyPath(path) {
    const pathArr = path.split('/')
    const n = pathArr.length
    const simplifiedPath = []

    for(let i=0; i<n; i++) {
        if(pathArr[i]==='.' || pathArr[i]==='') {
            continue
        }
        if(pathArr[i]==='..') {
            simplifiedPath.pop()
            continue
        }
        simplifiedPath.push(pathArr[i])
    }

    return `/${simplifiedPath.join('/')}`
}

Image container edge breakout

:root {
  --container-width: 700px;
  --columns: 12;
  --gap: 20px;
  --column-width: calc((var(--container-width) / var(--columns)) - var(--gap));
  --breakpoint: 46em;
}

img {
  max-width: 100%;
}


.image-edge-grid {
	margin-bottom: 2rem;
    display: grid;
    grid-gap: var(--gap);
    grid-template-columns: minmax(1em, 1fr) repeat(var(--columns), minmax(0, var(--column-width))) minmax(1em, 1fr);
    max-width: initial;
	
	
}




.image-edge-grid__img {
  grid-col