Cacher is the code snippet organizer for pro developers

.hoge{
  --lineColor: #fff;
  --lineSize: 1px;
  --spaceSize: 20px;
  background-image: linear-gradient(to right, var(--lineColor) var(--lineSize), transparent var(--lineSize)), linear-gradient(to bottom, var(--lineColor) var(--lineSize), transparent var(--lineSize));
  background-size: var(--spaceSize) var(--spaceSize);
  background-repeat: repeat;
}

# Add the following lines to ~/.zshrc                                                                                                                                 
# ===================================

# Apply green color to (.venv) in prompt in terminal                                        
export VIRTUAL_ENV_DISABLE_PROMPT=1                                                                                                                                          
setopt PROMPT_SUBST        

macros

```
/yell ¡INNER PLEASE!
/run local p=UnitPower("player")/UnitPowerMax("player")*100 SendChatMessage("MANA "..string.format("%.0f",p).."%","YELL")
```

```
/run local h=GetCombatRating(CR_HIT_MELEE) ChatFrame1:AddMessage(format("Hit:%d (%.2f%%)",h,h/32.79)) ChatFrame1:AddMessage(format("necessary 80:%d necessary 83:%d",math.max(0,164-h),math.max(0,263-h)))
```

![](https://cdn.cacher.io/attachments/u/3jyq9n8qej8bf/SsN3OYo8Y53JRNDr_RdyKKQGqk-PjsZE/wso23zliv.png)


```
/run local h=GetComb

/**
 * @param {string} s
 * @param {string} target
 * @return {string}
 */
var lexPalindromicPermutation = function (s, target) {
    const n = s.length;

    // Count frequency of each character in s
    const freq = new Array(26).fill(0);
    for (const ch of s) {
        freq[ch.charCodeAt(0) - 97]++;
    }

    // Check if a palindrome is even possible:
    // at most one character may have an odd count.
    let oddCount = 0;
    for (const x of freq) {
        if (x % 2 === 1) oddCount++;
 

com.hybris.backoffice.widgets.notificationarea.NotificationService
breakpoint

In the vast and often curated landscape of the internet, there are few platforms that offer the raw, unscripted spontaneity of Omegle. For over a decade, this unique website has served as a digital crossroads, connecting strangers from across the globe for one-on-one text or video chats. It’s a place where unexpected conversations bloom, fleeting connections are forged, and the truly bizarre can unfold at a moment's notice. If you’ve ever been curious about dipping your toes into this digital oc

Hansom
30
847
17th
bank transfer
second
swimming cap
gym
reception
6 a.m.
A
C
B
B
C
F
I
B
J
D


professional photographars
harm of chemicals

audience
research
statistic
quotations

real-time data

yields
user-friendly

natural resources-
farmmaps
improving
fixed-based
field GPS receiver

1. The Relentless Quizzing Prompt
You are an expert university professor. Your task is to relentlessly quiz me on the. Generate a 15-question cumulative quiz. Use a mix of: 5 Multiple-Choice Questions, 5 Fill-in-the-Blank Questions, and 5 Short-Answer Conceptual Questions. *Do not provide the answer key.* Wait for my response to each question, provide constructive feedback, and do not advance to the next question until I have answered the current one correctly.

2. Multiple Choice Quiz Prompt
Fo

/**
 * @param {string} s
 * @param {string} target
 * @return {string}
 */
var lexGreaterPermutation = function (s, target) {
    const n = s.length;

    // Frequency of each character in s: index 0 -> 'a', ..., 25 -> 'z'
    const freq = Array(26).fill(0);
    for (const ch of s) {
        freq[ch.charCodeAt(0) - 97]++;
    }

    // Answer we are constructing
    const ans = Array(n).fill('');

    /**
     * Step 1: Try to make ans equal to target as long as possible.
     * Returns the firs

## Symptoms

|Command|Return|ReturnCode|
|---|---|---|
|DISM.exe|Insufficient system resources exist to complete the requested service.|1450|
|SFC.exe|Windows Resource Protection could not perform the requested operation.||

```0x800705AA: ERROR_NO_SYSTEM_RESOURCES```<br>
```0xC000009A: STATUS_INSUFFICIENT_RESOURCES```

## Cause

COMPONENTS registry hive was so large that additional entries could not be written.

## Resolution

#### Step 1: Export Oldest VersionedIndex Registry Keys (to regain t

DROP PROCEDURE IF EXISTS moja_test_procedura;

DELIMITER //

CREATE PROCEDURE moja_test_procedura()
BEGIN
    -- 1. Deklarace handleru MUSÍ být na začátku bloku BEGIN
    DECLARE EXIT HANDLER FOR SQLEXCEPTION
    BEGIN
        ROLLBACK;
        SELECT 'Chyba! Transakce byla zrušena.' AS Vysledek;
    END;

    -- 2. Logika transakce
    START TRANSACTION;

    INSERT INTO icon_list VALUES (555, 'test', 'aaa');
    INSERT INTO icon_list VALUES (555, 'test', 'aaa');

    COMMIT;

# Run Django Python script in Powershell (outside PyCharm)

- Navigate to project root folder
- Activate virtual environment: -`.venv\Scripts\Activate.ps1`
- Run the script as a module using the `-m` flag and `.`` instead of ``\`: `python -m app.folder.script_name`
- Deactivate virtual environment: `deactivate`

/**
 * @param {string} s
 * @param {number} k
 * @return {string}
 */
var shortestBeautifulSubstring = function(s, k) {
    let n = s.length;
    let left = 0;
    let count1 = 0;
    let best = "";  // store lexicographically smallest among shortest

    for (let right = 0; right < n; right++) {
        if (s[right] === '1') count1++;

        // When we have exactly k ones, try shrinking from the left
        while (count1 === k) {
            let candidate = s.slice(left, right + 1);

       

    implementation("io.jsonwebtoken:jjwt-api:0.12.5")
    runtimeOnly("io.jsonwebtoken:jjwt-impl:0.12.5")
    runtimeOnly("io.jsonwebtoken:jjwt-jackson:0.12.5")

/**
 * @param {number[]} nums
 * @param {number} k
 * @return {number}
 */
var missingMultiple = function(nums, k) {
    // Use a Set for O(1) membership checks
    const seen = new Set(nums);

    // Start from the first positive multiple of k
    let m = k;

    // Keep checking multiples of k until one is not in nums
    while (seen.has(m)) {
        m += k;   // Move to the next multiple
    }

    // This is the smallest missing multiple
    return m;
};