How to create a service using the nest cli

nest g service [serviceName] [moduleNameForTheService]

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1513. Number of Substrings With Only 1s

Given a binary string s, return the number of substrings with all characters 1's. Since the answer may be too large, return it modulo 109 + 7.
/**
 * @param {string} s
 * @return {number}
 */
var numSub = function(s) {
    const MOD = 1_000_000_007; // Large prime for modulo operations
    let ans = 0;               // Final answer accumulator
    let run = 0;               // Current streak length of consecutive '1's

    for (let i = 0; i < s.length; i++) {
        if (s[i] === '1') {
            run += 1;                  // Extend the current streak
            ans = (ans + run) % MOD;   // Add substrings ending at this position
  

git gerrit客户端配置

# git gerrit客户端配置
## 客户端配置
- 安装 commit-msg hook,用于提交时生成Change-Id
```sh
curl -o .git/hooks/commit-msg \
  http://gerrit-server:8080/tools/hooks/commit-msg
chmod +x .git/hooks/commit-msg
```
- 配置git review
```sh
# 安装 git-review
pip install git-review

# 或在项目目录配置
git config remote.origin.pushurl ssh://username@gerrit-server:29418/your-project
# 配置推送分支映射到远端refs/for/路径下以支持远端审核
git config remote.origin.push refs/heads/*:refs/for/*
```
## 验证本地是否配置正确
1.检查`.git/hooks`下是否存在`commit-msg`文件,且内容类似:
```sh
#!/b

swift语法注意事项:三元表达式

# swift语法注意事项:三元表达式
## 报错
```swift
print("【\(text)】---\((result? "匹配": "不匹配"))")
```
## 不报错
```swift
print("【\(text)】---\((result ? "匹配": "不匹配"))")
```
## 注意
**`三元运算符中?之前必须至少要有一个空格否则会和可选链语法冲突导致报错`**

How to create a module using the nest cli

nest g controller [controllerName] [moduleNameForTheControlle]

How to create a module using the nest cli

nest g module [modulename]

3234. Count the Number of Substrings With Dominant Ones

You are given a binary string s. Return the number of substrings with dominant ones. A string has dominant ones if the number of ones in the string is greater than or equal to the square of the number of zeros in the string.
/**
 * @param {string} s
 * @return {number}
 */
let numberOfSubstrings = function (s) {
    const n = s.length;

    // dp[i] stores the nearest index <= i where a '0' occurs
    // (or -1 if none). This helps us quickly jump backwards
    // to substrings that include more zeros.
    const dp = Array(n + 1).fill(-1);

    // Build the dp array
    for (let i = 0; i < n; i++) {
        if (i === 0 || s[i - 1] === '0') {
            // If at start OR previous char was '0',
            // mark cu

Tiny usefull composables

// useFormHandler.js
import { ref } from 'vue'

export function useFormHandler(initialData = {}) {
  const formData = ref({ ...initialData })
  const errors = ref({})
  const validate = () => {
    errors.value = {}
    Object.keys(formData.value).forEach(key => {
      if (!formData.value[key]) errors.value[key] = 'Required'
    })
    return Object.keys(errors.value).length === 0
  }
  return { formData, errors, validate }
}

// ======================================= // 

//

Animations - Metallic Paint

npx shadcn@latest add @react-bits/MetallicPaint-TS-CSS

Animation - Electric Border

npx shadcn@latest add @react-bits/ElectricBorder-TS-CSS

Body text - Glitch Text

npx shadcn@latest add @react-bits/GlitchText-TS-CSS

Title Text - Decrypted Text

npx shadcn@latest add @react-bits/DecryptedText-TS-CSS

Components - Magic Bento

npx shadcn@latest add @react-bits/MagicBento-TS-CSS

Background - Lighting effect

npx shadcn@latest add @react-bits/Lightning-TS-CSS

2536. Increment Submatrices by One

You are given a positive integer n, indicating that we initially have an n x n 0-indexed integer matrix mat filled with zeroes. You are also given a 2D integer array query. For each query[i] = [row1i, col1i, row2i, col2i], you should do the following operation: Add 1 to every element in the submatrix with the top left corner (row1i, col1i) and the bottom right corner (row2i, col2i). That is, add 1 to mat[x][y] for all row1i <= x <= row2i and col1i <= y <= col2i. Return the matrix mat after performing every query.
/**
 * @param {number} n
 * @param {number[][]} queries
 * @return {number[][]}
 */
var rangeAddQueries = function(n, queries) {
    // Step 1: Initialize an n x n matrix filled with 0s
    let mat = Array.from({ length: n }, () => Array(n).fill(0));

    // Step 2: Process each query
    for (let [row1, col1, row2, col2] of queries) {
        // Loop through the submatrix defined by the query
        for (let r = row1; r <= row2; r++) {
            for (let c = col1; c <= col2; c++) {