AJAX 表单传输 GET方法
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<script>
function showHint(str){
var xmlhttp;
if (str.length==0){
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest){
// IE7+, Firefox, Chrome, Opera, Safari 浏览器执行代码
xmlhttp=new XMLHttpRequest();
}
else{
// IE6, IE5 浏览器执行代码
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function(){
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","/try/ajax/gethint.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<h3>在输入框中尝试输入字母 a:</h3>
<form action="">
输入姓名: <input type="text" id="txt1" onkeyup="showHint(this.value)" />
</form>
<p>提示信息: <span id="txtHint"></span></p>
</body>
</html>