BZbyr
11/1/2017 - 1:12 AM

AJAX_表单_GET

AJAX 表单传输 GET方法

<!DOCTYPE html>
<html>
  <head>
  <meta charset="utf-8">
  <script>
  function showHint(str){
    var xmlhttp;
    if (str.length==0){ 
      document.getElementById("txtHint").innerHTML="";
      return;
    }
    if (window.XMLHttpRequest){
      // IE7+, Firefox, Chrome, Opera, Safari 浏览器执行代码
      xmlhttp=new XMLHttpRequest();
    }
    else{
      // IE6, IE5 浏览器执行代码
      xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
    }
    xmlhttp.onreadystatechange=function(){
      if (xmlhttp.readyState==4 && xmlhttp.status==200)
      {
        document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
      }
    }
    xmlhttp.open("GET","/try/ajax/gethint.php?q="+str,true);
    xmlhttp.send();
  }
  </script>
  </head>
  <body>
  
  <h3>在输入框中尝试输入字母 a:</h3>
  <form action=""> 
  输入姓名: <input type="text" id="txt1" onkeyup="showHint(this.value)" />
  </form>
  <p>提示信息: <span id="txtHint"></span></p> 
  
  </body>
</html>