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// solution 1, iterative version
int get_sum(int A[], int N) {
    	if(N == 0) return 0;
	if(N == 1) return A[0];
	int *S = new int[N];
	S[0] = A[0];
	S[1] = max(A[0], A[1]);
	for(int i=2; i<N; i++)
		S[i] = max(A[i], max(S[i-1], S[i-2] + A[i])); // gist!!! cannot forget A[i]
	return S[N-1];
}

// solution 2, recursive version
int get_sum2(int A[], int i) {
    	if(i == 0) return 0;
    	if(i == 1) return A[0];
    	return max(get_sum2(A, i-1), A[i] + get_sum2(A, i-2));
}

int main()
{
   	int A[] = {5,  5, 10, 40, 50, 35};
   	cout << get_sum(A, 6) << endl;
   	cout << get_sum2(A, 6);
   
   	return 0;
}