sequence
const plusOne = x => x + 1;
const plusTwo = x => x + 2;
const plusThree = x => x + 3;
// R.converge((...args) => args, [plusOne, plusTwo, plusThree])(1); // => [2, 3, 4]
// juxt([plusOne, plusTwo, plusThree])(1) // => [2, 3, 4]
sequence(always, [plusOne, plusTwo, plusThree])(1) // => [2, 3, 4]
/////////////////////////////////////////////////////////////////////////////////
const getTimeFromStart = startTime => Date.now() - startTime;
const makeFuture = startTime => ms => Future((reject, resolve) => {
console.log('start: ' + ms, 'timeFromStart: ' + getTimeFromStart(startTime));
return setTimeout(() => {
console.log('finish: ' + ms, 'timeFromStart: ' + getTimeFromStart(startTime));
resolve(ms);
}, ms)
});
const futureOfMs = makeFuture(Date.now());
const futuRes = R.sequence(Future.of, [futureOfMs(1000), futureOfMs(3000), futureOfMs(5000)]);
futuRes.fork(err => console.error(err), data => console.log(data)); //=>
// start: 1000
// timeFromStart: 0
// start: 5000
// timeFromStart: 0
// start: 3000
// timeFromStart: 1
// finish: 1000
// timeFromStart: 1001
// finish: 3000
// timeFromStart: 3003
// finish: 5000
// timeFromStart: 5003
// [1000,5000,3000]
// So, method starts all the futures simultaneously. It returns results according to a preassigned order.