Sum of non-repeated elements
/*
http://ideone.com/hUqkKD
http://www.practice.geeksforgeeks.org/problem-page.php?pid=530
*/
#include <iostream>
using namespace std;
int main() {
// your code goes here
int i, n;
cin >> i;
while(i--){
cin >> n;
int count[1001] = {-1}, x;
for(int i=0; i<n; i++){
cin >> x;
count[x]++;
}
int sum =0;
for(int i=1; i<1001; i++){
if(count[i] >= 1)
sum += i;
}
cout << sum << endl;
}
return 0;
}