jweinst1

10/28/2016 - 10:40 PM

```
#Generator practice with classes
class Link:
def __init__(self, first, next=None):
self.first = first
self.next = next
def __repr__(self):
return "({0}, {1})".format(self.first, self.next)
#Question 1
#Define a generator that on each next() call, returns a linked list of
#numbers from 0 to infinity, making the chain one link longer each time
"""
f = lazy_numbers()
=> None
next(f)
=> (0, None)
next(f)
=> (0, (1, None))
next(f)
=> (0, (1, (2, None)))
next(f)
=> (0, (1, (2, (3, None))))
next(f)
=> (0, (1, (2, (3, (4, None)))))
next(f)
=> (0, (1, (2, (3, (4, (5, None))))))
next(f)
=> (0, (1, (2, (3, (4, (5, (6, None)))))))
"""
def lazy_numbers():
pass
#Question 2
#define a generator that yields the sequence of strings of integers from 1 to infinity, with each next() call returning the next string.
#You cannot use integers for this problem. You must construct integers with strings
#Hint the .join method of an empty string joins an array of strings together
# "".join(["a", "b"]) => "ab"
"""
f = intseq()
=> None
next(f)
=> '1'
next(f)
=> '2'
next(f)
=> '3'
next(f)
=> '4'
next(f)
=> '5'
next(f)
=> '6'
next(f)
=> '7'
next(f)
=> '8'
next(f)
=> '9'
next(f)
=> '10'
"""
def intseq():
pass
"""String Drawing Practice"""
#Question 3
#Define a generator that draws a zigzag line, of some width w. it will generate an infinite number of moving lines
#to mark the line use a star *
#HINT:use the join method here
def zigzag(w):
pass
```