Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10
Output: 1024.00000
Example 2:
Input: 2.10000, 3
Output: 9.26100
Example 3:
Input: 2.00000, -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25
Note:
class Solution {
public:
double myPow(double x, int n) {
double ans = 1;
unsigned long long p;
if (n < 0) {
p = -n;
x = 1 / x;
}
else
p = n;
while (p) {
if (p & 1)
ans *= x;
x *= x;
p >>= 1;
}
return ans;
}
};