chris-ELM
2/18/2016 - 5:46 PM

gets the name of the scene - requires use of getCourselayout() and also passing a scene number.

gets the name of the scene - requires use of getCourselayout() and also passing a scene number.

getSceneName.js
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function getSceneName(xmlIn, scNum) {
    var scn = xmlDoc.getElementsByTagName("links")[0].childNodes[scNum].getAttribute('displaytext')
    return scn;
}