# Definition for a undirected graph node
# class UndirectedGraphNode:
# def __init__(self, x):
# self.label = x
# self.neighbors = []
class Solution:
# @param node, a undirected graph node
# @return a undirected graph node
def cloneGraph(self, node):
if node == None:
return None
queue = []
self.dict = {}
cloneNode = UndirectedGraphNode(node.label)
queue.append(node)
self.dict[node] = cloneNode
while len(queue) != 0:
curNode = queue[0]
del queue[0]
curCloneNode = self.getOrCreate(curNode)
for eachNode in curNode.neighbors:
if self.dict.has_key(eachNode):
curCloneNode.neighbors.append(self.dict[eachNode])
else:
curCloneNode.neighbors.append(self.getOrCreate(eachNode))
queue.append(eachNode)
return cloneNode
def getOrCreate(self, node):
if self.dict.has_key(node):
return self.dict[node]
else:
cloneNode = UndirectedGraphNode(node.label)
self.dict[node] = cloneNode
return cloneNodehttps://leetcode.com/problems/clone-graph/#/description
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization: Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
0. Connect node 0 to both nodes 1 and 2.1. Connect node 1 to node 2.2. Connect node 2 to node 2 (itself), thus forming a self-cycle.Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/