class Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
recd = [-1] * 256
start = 0; max_len = 0
for end in range(len(s)):
if recd[ord(s[end])] >= start:
start = recd[ord(s[end])] + 1
recd[ord(s[end])] = end
max_len = max(end - start + 1, max_len)
return max_len
class Solution(object):
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
recd = [False] * 256
start = 0; max_len = 0
for end in range(len(s)):
if recd[ord(s[end])] == True:
while s[start] != s[end]:
recd[ord(s[start])] = False
start += 1
start += 1
recd[ord(s[end])] = True
max_len = max(end - start + 1, max_len)
return max_len
https://leetcode.com/problems/longest-substring-without-repeating-characters/#/description
Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb"
, the answer is "abc"
, which the length is 3.
Given "bbbbb"
, the answer is "b"
, with the length of 1.
Given "pwwkew"
, the answer is "wke"
, with the length of 3. Note that the answer must be a substring, "pwke"
is a subsequence and not a substring.