257-Binary-Tree-Paths https://leetcode.com/problems/binary-tree-paths/
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
# @param {TreeNode} root
# @return {string[]}
def binaryTreePaths(self, root):
self.pathRecd = []
if root == None:
return self.pathRecd
self.findPath(root, str(root.val))
return self.pathRecd
def findPath(self, root, pathString):
if root.left == None and root.right == None:
self.pathRecd.append(pathString)
if root.left != None:
self.findPath(root.left, pathString+'->'+str(root.left.val))
if root.right != None:
self.findPath(root.right, pathString+'->'+str(root.right.val))
Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1
/ \
2 3
\
5
All root-to-leaf paths are:
["1->2->5", "1->3"]