# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def levelOrder(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if root == None:
return []
queue = [root]
res = []
curLevel = []
rightmost = root
while len(queue) != 0:
curNode = queue[0]
del queue[0]
curLevel.append(curNode.val)
if curNode.left:
queue.append(curNode.left)
if curNode.right:
queue.append(curNode.right)
if curNode == rightmost:
res.append(curLevel)
if len(queue) != 0:
rightmost = queue[-1]
curLevel = []
return res
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def levelOrder(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if root == None:
return []
queue = [root]
res = []
while len(queue) != 0:
curLevel = []
for i in range(len(queue)):
node = queue[0]
del queue[0]
curLevel.append(node.val)
if node.left:
queue.append(node.left)
if node.right:
queue.append(node.right)
res.append(curLevel)
return res
https://leetcode.com/problems/binary-tree-level-order-traversal/#/description
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
For example:
Given binary tree [3,9,20,null,null,15,7]
,
3
/ \
9 20
/ \
15 7
return its level order traversal as:
[
[3],
[9,20],
[15,7]
]