suibenzhi
7/13/2018 - 3:44 PM

复杂链表的复制.cpp

//输入一个复杂链表(每个节点中有节点值,以及两个指针,一个指向下一个节点,另一个特殊指针指向任意一个节点),返回结果为复制后复杂链表的head。(注意,输出结果中请不要返回参数中的节点引用,否则判题程序会直接返回空)

/*
struct RandomListNode {
    int label;
    struct RandomListNode *next, *random;
    RandomListNode(int x) :
            label(x), next(NULL), random(NULL) {
    }
};
*/


RandomListNode* Clone(RandomListNode* pHead)
{
            if(NULL == pHead) return NULL;
 
     
    RandomListNode* pNewHead, *pNode;
    pNode = pHead;
    while(NULL != pNode)
    {
        RandomListNode* pNewNode = new RandomListNode(pNode->label);
        pNewNode->next = pNode->next;
        pNode->next = pNewNode;
        pNode = pNewNode->next;
         
    }
     
    pNode = pHead;
    while(NULL != pNode)
    {  
        if(NULL != pNode->random)
        {
            pNode->next->random = pNode->random->next;
        }
        pNode = pNode->next->next;       
    }
 
    pNewHead = pHead->next;
    pNode = pHead;
    RandomListNode* temp;
    while(NULL != pNode->next)
    {
        temp = pNode->next;
        pNode->next = temp->next;
        pNode = temp;
    }
     
    return pNewHead;
}