moonlightshadow123
6/22/2017 - 4:19 AM

103. Binary Tree Zigzag Level Order Traversal

  1. Binary Tree Zigzag Level Order Traversal
# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def zigzagLevelOrder(self, root):
        """
        :type root: TreeNode
        :rtype: List[List[int]]
        """
        if root == None:
            return []
        self.res = []
        self.DFS(root, 1, True)
        return self.res
    def DFS(self, node, level, left2Right):
        if node == None:
            return
        if len(self.res) < level:
            self.res.append([])
        if left2Right:
            self.res[level-1].append(node.val)
        else:
            self.res[level-1].insert(0, node.val)
        self.DFS(node.left, level+1, not left2Right)
        self.DFS(node.right, level+1, not left2Right)

https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/#/description

Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).

For example: Given binary tree [3,9,20,null,null,15,7],

    3
   / \
  9  20
    /  \
   15   7

return its zigzag level order traversal as:

[
  [3],
  [20,9],
  [15,7]
]