Find maximum length subarray with equal number of 1s and 0s
import java.util.*;
public class MaxSubArrayEqual1sAnd0s {
public static void main(String args[]) {
MaxSubArrayEqual1sAnd0s maxSubArray = new MaxSubArrayEqual1sAnd0s();
int[][] input = {
null,
{},
{0},
{1},
{1,0},
{0,1,0},
{0,0,1,0,1,0,0}
};
for(int i=0; i< input.length; i++) {
System.out.println("Input: " + Arrays.toString(input[i]) + ", Result: " + Arrays.toString(maxSubArray.maxLengthArray(input[i])));
}
}
public int[] maxLengthArray(int[] input) {
if(input == null || input.length == 0) {
return input;
}
// CurrentSum, Index
Map<Integer, Integer> sumIndexTracker = new HashMap<>();
// To address input array which begins with 0
sumIndexTracker.put(0,-1);
int currentSum = 0;
int start = 0;
int end = 0;
int maxLen = 0;
for(int i=0; i< input.length; i++) {
int currentValue = (input[i] == 0) ? -1:1;
currentSum += currentValue;
if(!sumIndexTracker.containsKey(currentSum)) {
sumIndexTracker.put(currentSum, i);
} else {
if(maxLen < i - sumIndexTracker.get(currentSum)) {
start = sumIndexTracker.get(currentSum) + 1;
end = i;
maxLen = end - start + 1;
}
}
}
return extract(input, start, end);
}
private int[] extract(int[] input, int start, int end) {
int[] extracted = new int[end - start + 1];
int j = 0;
for(int i=start; i<= end; i++) {
extracted[j++] = input[i];
}
return extracted;
}
}