scosant
12/17/2012 - 11:14 AM

## projecteuler022 - name scores

projecteuler022 - name scores

``````"""
Scott Santarromana
projecteuler022 - name scores

Using names.txt (right click and 'Save Link/Target As...'), a 46K text file
containing over five-thousand first names, begin by sorting it into
alphabetical order. Then working out the alphabetical value for each name,
multiply this value by its alphabetical position in the list to obtain a name
score.

For example, when the list is sorted into alphabetical order, COLIN, which is
worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN
would obtain a score of 938  53 = 49714.

What is the total of all the name scores in the file?
"""
import csv

def calc_name_val(name):
val = 0
for c in name:
val += ord(c) - 64
return val

names_file = csv.reader(open('./projecteuler022.txt', 'rb'), delimiter=',', quotechar='"')
sum = 0
for row in names_file:
for idx, name in enumerate(sorted(row)):
name_val = calc_name_val(name)
print str(idx) + ' ' + name + ' ' + str(name_val)
sum += name_val * (idx + 1)
print sum

``````