class Solution(object):
def isPalindrome(self, s):
"""
:type s: str
:rtype: bool
"""
def isAlpha(char):
if ord(char) >= ord('A') and ord(char) <= ord('Z'):
return True
elif ord(char) >= ord('a') and ord(char) <= ord('z'):
return True
elif ord(char) >= ord('0') and ord(char) <= ord('9'):
return True
return False
n = len(s);
if n == 0: return True
s = s.lower()
start = 0; end = n-1
while start < end:
if not isAlpha(s[start]):
start += 1
continue
if not isAlpha(s[end]):
end -= 1
continue
if s[start] != s[end]:
print start,end
return False
start += 1; end -= 1
return True
https://leetcode.com/problems/valid-palindrome/#/description
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
"A man, a plan, a canal: Panama"
is a palindrome.
"race a car"
is not a palindrome.