kaioe
6/16/2015 - 3:25 PM

JQueryAjax

JQueryAjax

    /* Act on the event */
    var data_content = 'Some Content';

    console.log(data_content);

    $.ajax({
      url:'control.php',
      type:'POST',
      data: data_content, 
      success: loadNextEvent,
      error: function(xhr, desc, err) { console.log(xhr + "| Details: " + desc + "\nError:" + err); }
    })
    .done(function() {
      alert( "success" );
    })
    .fail(function() {
      alert( "error" );
    })
    .always(function() {
      alert( "complete" );
    });