3614. Process String with Special Operations II

You are given a string s consisting of lowercase English letters and the special characters: '*', '#', and '%'. You are also given an integer k. Build a new string result by processing s according to the following rules from left to right: If the letter is a lowercase English letter append it to result. A '*' removes the last character from result, if it exists. A '#' duplicates the current result and appends it to itself. A '%' reverses the current result. Return the kth character of the final string result. If k is out of the bounds of result, return '.'.
/**
 * @param {string} s
 * @param {number} k
 * @return {character}
 */
var processStr = function(s, k) {
    const n = s.length;
    const len = new Array(n).fill(0);

    // Forward: compute lengths
    for (let i = 0; i < n; i++) {
        const c = s[i];
        if (c >= 'a' && c <= 'z') {
            len[i] = (i > 0 ? len[i-1] : 0) + 1;
        } else if (c === '*') {
            len[i] = Math.max(0, (i > 0 ? len[i-1] : 0) - 1); 
        } else if (c === '#') {
            len[i] = (i > 0 

Codice Fiscale Italiano Regex

```
^[A-Za-z]{6}[0-9]{2}[A-Za-z][0-9]{2}[A-Za-z][0-9]{3}[A-Za-z]$
```

Export network agents email addresses from outlook to csv to be imported to sendmsg - VBA Outlook Macro

Option Explicit

Function GetRecipientSMTPAddress(recip As Outlook.Recipient) As String

    Dim pa As Outlook.PropertyAccessor
    Dim smtpAddress As String
    Dim exchUser As Outlook.ExchangeUser

    On Error Resume Next

    If recip.AddressEntry.Type = "EX" Then
        Set exchUser = recip.AddressEntry.GetExchangeUser

        If Not exchUser Is Nothing Then
            smtpAddress = exchUser.PrimarySmtpAddress
        End If
    End If

    If smtpAddress = "" Then
   

how to run a logged test on canada billpyament

E2E_AUTH_TOKEN='JWT' E2E_BASE_URL='http://localhost:3002/' npx playwright test

3612. Process String with Special Operations I

You are given a string s consisting of lowercase English letters and the special characters: *, #, and %. Build a new string result by processing s according to the following rules from left to right: If the letter is a lowercase English letter append it to result. A '*' removes the last character from result, if it exists. A '#' duplicates the current result and appends it to itself. A '%' reverses the current result. Return the final string result after processing all characters in s.
/**
 * @param {string} s
 * @return {string}
 */
var processStr = function(s) {
    let res = [];

    for (const ch of s) {
        if (ch >= 'a' && ch <= 'z') {
            // Append letter
            res.push(ch);

        } else if (ch === '*') {
            // Remove last char if exists
            if (res.length > 0) res.pop();

        } else if (ch === '#') {
            // Duplicate the entire result
            res = res.concat(res);

        } else if (ch === '%') {
            // Re

Top Mem Setup

# topmem Script Setup Notes

**Machine:** Lenovo ThinkPad T14 Gen 2
**OS:** Ubuntu 24.04 LTS (Dual Boot)
**Date:** March 24, 2026

---

## Overview

`topmem` is a shell script that shows memory usage aggregated by process name. Unlike `ps aux` which lists every individual process instance separately, `topmem` collapses multiple instances of the same program (e.g. multiple `node` or `chrome` processes) and shows their combined memory footprint — making it easy to answer "which application is usin

Top Cpu Setup

# topcpu Script Setup Notes

**Machine:** Lenovo ThinkPad T14 Gen 2
**OS:** Ubuntu 24.04 LTS (Dual Boot)
**Date:** March 24, 2026

---

## Overview

`topcpu` is a shell script that shows CPU usage aggregated by process name. Unlike `ps aux` which lists every individual process instance separately, `topcpu` collapses multiple instances of the same program (e.g. multiple `node` or `chrome` processes) and shows their combined CPU footprint — making it easy to answer "which application is consuming 

Monitoring - Top Mem with Watcher

#!/bin/bash

WATCH=false
INTERVAL=30
COUNT=10

if [[ "$1" == "-w" ]]; then
    WATCH=true
    [[ -n "$2" && "$2" =~ ^[0-9]+$ ]] && INTERVAL="$2"
elif [[ -n "$1" ]]; then
    COUNT="$1"
fi

run() {
    free -h | awk '/^Mem:/ {printf "Memory: %s used / %s total\n", $3, $2}'
    echo "────────────────────────────────────────"
    ps aux | awk 'NR>1 {mem[$11]+=$4} END {for (p in mem) printf "%6.2f%% %s\n", mem[p], p}' | sort -nr | head -n "$COUNT"
}

if $WATCH; then
    while true; do
        clear

Monitoring - Top Cpu with Watcher

#!/bin/bash

WATCH=false
INTERVAL=30
COUNT=10

if [[ "$1" == "-w" ]]; then
    WATCH=true
    [[ -n "$2" && "$2" =~ ^[0-9]+$ ]] && INTERVAL="$2"
elif [[ -n "$1" ]]; then
    COUNT="$1"
fi

run() {
    cpu_used=$(top -bn1 | grep '%Cpu' | awk '{printf "%.1f", 100 - $8}')
    cores=$(nproc)
    printf "CPU: %s%% used / %s cores total\n" "$cpu_used" "$cores"
    echo "────────────────────────────────────────"
    ps aux | awk 'NR>1 {cpu[$11]+=$3} END {for (p in cpu) printf "%6.2f%% %s\n", cpu[p], p}

BlogPosting schema

<script type="application/ld+json">
[
  {
    "@context": "https://schema.org",
    "@type": "BlogPosting",
    "headline": {{ article.title | json }},
    "description": {% if article.excerpt != blank %}{{ article.excerpt | strip_html | truncate: 300 | json }}{% else %}{{ article.content | strip_html | truncate: 300 | json }}{% endif %},
    "image": [
      {% if article.image != blank %}{{ article.image | image_url: width: 800 | prepend: 'https:' | json }}{% else %}""{% endif %}
    ],
    "a

2095. Delete the Middle Node of a Linked List

You are given the head of a linked list. Delete the middle node, and return the head of the modified linked list. The middle node of a linked list of size n is the ⌊n / 2⌋th node from the start using 0-based indexing, where ⌊x⌋ denotes the largest integer less than or equal to x. For n = 1, 2, 3, 4, and 5, the middle nodes are 0, 1, 1, 2, and 2, respectively.
/**
 * Definition for singly-linked list.
 * function ListNode(val, next) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.next = (next===undefined ? null : next)
 * }
 */
/**
 * @param {ListNode} head
 * @return {ListNode}
 */
var deleteMiddle = function(head) {
    // 1. Edge case: only one node
    if (!head.next) return null;

    // 2. Find the node BEFORE the middle
    let slow = head;
    let fast = head.next.next;

    while (fast && fast.next) {
        slow = slow.next;
   

Получение xml заказа

/bitrix/admin/1c_exchange.php?type=sale&mode=checkauth
/bitrix/admin/1c_exchange.php?type=sale&mode=init&sessid=ID_Сессии
/bitrix/admin/1c_exchange.php?type=sale&mode=query&sessid=ID_Сессии

IELTS 5 -12

B
B
C
C
A
hills
bus
5
picnic
map
B
E
D - A
F
G
D
B
C
I - H
A
D
A
H
E - B
G
sand
lower part
? undercut
? the coastguard
mobile phones
personality
numerous  - mean
verbal
psychological 
? literacy
extremes
assessment? - interpretation
brain damage
school
reliability

Vocabulary:
red tape
ears poped

image.md

Here are five distinct iterations of the Chicano tattoo-style theme, each expanding the narrative and scenery while maintaining the fineline black-and-grey aesthetic on vintage parchment.

### 1. The Boulevard Cruise
This scene shifts focus to a late-night cruise down Whittier Boulevard. The **Chevrolet lowrider** is depicted in motion, its front end hopped high in a "three-wheel motion" stance, captured with dynamic motion lines and blurred stippling. The **two skeleton figures** are seated 

2130. Maximum Twin Sum of a Linked List

In a linked list of size n, where n is even, the ith node (0-indexed) of the linked list is known as the twin of the (n-1-i)th node, if 0 <= i <= (n / 2) - 1. For example, if n = 4, then node 0 is the twin of node 3, and node 1 is the twin of node 2. These are the only nodes with twins for n = 4. The twin sum is defined as the sum of a node and its twin. Given the head of a linked list with even length, return the maximum twin sum of the linked list.
/**
 * Definition for singly-linked list.
 * function ListNode(val, next) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.next = (next===undefined ? null : next)
 * }
 */
/**
 * @param {ListNode} head
 * @return {number}
 */
var pairSum = function(head) {
    // 1. Find middle using slow/fast pointers
    let slow = head, fast = head;
    while (fast && fast.next) {
        slow = slow.next;
        fast = fast.next.next;
    }

    // 2. Reverse second half
    let prev = null, curr

Claude - Settings

{
  "outputStyle": "Explanatory",
  "enableAllProjectMcpServers": true,
  "permissions": {
    "defaultMode": "acceptEdits",
    "allow": ["Read", "Skill", "Bash", "Ide*", "WebSearch", "WebFetch", "mcp__*"]
  }
}