chatGPT

Je veux comprendre Fabric en profondeur.

Mon niveau : développeur Python/Django.

Explique-moi d’abord le problème que cette technologie résout, 

Puis les concepts clés, puis un exemple simple, puis un cas réel professionnel. 

Pose-moi des questions pour vérifier ma compréhension.

Linux Custom - Basic Shell Prompt

export PS1="\n\
\[\033[38;2;255;249;143m\] \w\n\
\[\033[38;2;255;90;91m\] ⏹\
\[\033[38;2;250;190;36m\]⏹\
\[\033[38;2;42;197;67m\]⏹\
\[\033[0m\] \
\[\033[38;2;120;150;255m\]ubuntu-clean \
\[\033[38;2;140;170;255m\]❱ \
\[\033[0m\] "

Linux Custom - Basic Alias

SUDO() {
    if [ "$(id -u)" -ne 0 ] && command -v sudo >/dev/null 2>&1; then
        sudo "$@"
    else
        "$@"
    fi
}

cc() {
    if command -v tput >/dev/null 2>&1 && [ -n "${TERM:-}" ] && tput reset 2>/dev/null; then
        return
    fi

    clear
}

alias apti='SUDO apt install -y'
alias aptu='SUDO apt update'
alias aptcc='SUDO apt autoremove -y && SUDO apt-get autoclean'
alias aptc='SUDO apt clean'
alias aptup='SUDO apt update && SUDO apt upgrade -y'

alias mkdir='mkdir -p'

alias

3559. Number of Ways to Assign Edge Weights II

There is an undirected tree with n nodes labeled from 1 to n, rooted at node 1. The tree is represented by a 2D integer array edges of length n - 1, where edges[i] = [ui, vi] indicates that there is an edge between nodes ui and vi. Initially, all edges have a weight of 0. You must assign each edge a weight of either 1 or 2. The cost of a path between any two nodes u and v is the total weight of all edges in the path connecting them. You are given a 2D integer array queries. For each queries[i] = [ui, vi], determine the number of ways to assign weights to edges in the path such that the cost of the path between ui and vi is odd. Return an array answer, where answer[i] is the number of valid assignments for queries[i]. Since the answer may be large, apply modulo 109 + 7 to each answer[i]. Note: For each query, disregard all edges not in the path between node ui and vi.
/**
 * @param {number[][]} edges
 * @param {number[][]} queries
 * @return {number[]}
 */
var assignEdgeWeights = function(edges, queries) {
    const n = edges.length + 1;
    const g = Array.from({ length: n + 1 }, () => []);

    for (const [u, v] of edges) {
        g[u].push(v);
        g[v].push(u);
    }

    // --- 1) BFS to compute depth + parent[0] ---
    const LOG = 17; // since n <= 1e5, log2(1e5) < 17
    const parent = Array.from({ length: LOG }, () => Array(n + 1).fill(0));
    c

hide sticky elementor claude

@media (min-width: 320px) and (max-width: 767px) {
  
  .e-con-full.e-flex.e-con.e-child {
    position: relative;
}
  
}

Settings Basiques VS Code

{
  // ============================================================
  // Settings VS Code — poste corporate
  // Périmètre : core VS Code + GitHub Copilot uniquement.
  // Exclus : settings liés aux extensions tierces (Ruff, Pylance,
  // YAML, TOML, Terraform, Material Icons, Gemini) — à réintégrer
  // au fil des approbations du circuit d'allowlisting interne.
  // ============================================================

  // --- UI & Affichage (core) ---
  "window.zoomLevel": 0,
  "workb

3558. Number of Ways to Assign Edge Weights I

There is an undirected tree with n nodes labeled from 1 to n, rooted at node 1. The tree is represented by a 2D integer array edges of length n - 1, where edges[i] = [ui, vi] indicates that there is an edge between nodes ui and vi. Initially, all edges have a weight of 0. You must assign each edge a weight of either 1 or 2. The cost of a path between any two nodes u and v is the total weight of all edges in the path connecting them. Select any one node x at the maximum depth. Return the number of ways to assign edge weights in the path from node 1 to x such that its total cost is odd. Since the answer may be large, return it modulo 109 + 7. Note: Ignore all edges not in the path from node 1 to x.
/**
 * @param {number[][]} edges
 * @return {number}
 */
var assignEdgeWeights = function(edges) {
    const n = edges.length + 1;
    const g = Array.from({ length: n + 1 }, () => []);

    for (const [u, v] of edges) {
        g[u].push(v);
        g[v].push(u);
    }

    // BFS to compute depths from node 1
    const depth = Array(n + 1).fill(-1);
    const queue = [1];
    depth[1] = 0;

    while (queue.length) {
        const u = queue.shift();
        for (const v of g[u]) {
            

3691. Maximum Total Subarray Value II

You are given an integer array nums of length n and an integer k. You must select exactly k distinct subarrays nums[l..r] of nums. Subarrays may overlap, but the exact same subarray (same l and r) cannot be chosen more than once. The value of a subarray nums[l..r] is defined as: max(nums[l..r]) - min(nums[l..r]). The total value is the sum of the values of all chosen subarrays. Return the maximum possible total value you can achieve.
/**
 * @param {number[]} nums
 * @param {number} k
 * @return {number}
 */
var maxTotalValue = function(nums, k) {
    const n = nums.length;

    // -----------------------------
    // 1. Build Sparse Tables for RMQ
    // -----------------------------
    const LOG = Math.floor(Math.log2(n)) + 1;
    const stMax = Array.from({ length: LOG }, () => Array(n).fill(0));
    const stMin = Array.from({ length: LOG }, () => Array(n).fill(0));

    // level 0 is the array itself
    for (let i = 0; i

choose between different merge strategies in git

ayuda:   git config pull.rebase false  # fusionar
ayuda:   git config pull.rebase true   # rebasar
ayuda:   git config pull.ff only       # solo avance rápido

when that appears I allways select the first one: fusionar

A Dive into the World of Omegle

In the vast ocean of the internet, where connections are made and conversations spark, there’s a unique platform that has captivated millions: Omegle. For those unfamiliar, Omegle is a free online chat website that allows users to socialize with others without the need to register. It’s a fascinating, sometimes chaotic, and often surprising experience, and today, we're going to explore how to navigate its intriguing waters.
What is [Omegle](https://omezy.io)? And How Does it Work?
At its core,

pwd projduct manajer/



i want to create a project manager for my ai agency, using mastra.ai and mongodb for observeable memory and vector store as well. the agent needs to have acees to the web with exa.ai web search. it needs to keep linear and github in sync, as well as monday.com. it is to delagate work, not complete work,  after it breaks down the task into pieces , it then passes the work outto its teammates.  from then it monitors the  the progress of the other agents. if they get stuck he is  too assist and

3689. Maximum Total Subarray Value I

You are given an integer array nums of length n and an integer k. You need to choose exactly k non-empty subarrays nums[l..r] of nums. Subarrays may overlap, and the exact same subarray (same l and r) can be chosen more than once. The value of a subarray nums[l..r] is defined as: max(nums[l..r]) - min(nums[l..r]). The total value is the sum of the values of all chosen subarrays. Return the maximum possible total value you can achieve.
/**
 * @param {number[]} nums
 * @param {number} k
 * @return {number}
 */
var maxTotalValue = function(nums, k) {
    // We want to maximize: max(subarray) - min(subarray)
    // And since we are allowed to pick the SAME subarray multiple times,
    // we only need to find the single subarray with the highest possible value.

    // The subarray that maximizes (max - min) is always the ENTIRE array,
    // because:
    //   - max of any subarray ≤ max of whole array
    //   - min of any subarr

updated prompt

# Role and Objective
Craft a vivid, compositionally coherent illustration prompt in a fineline black-and-grey Chicano tattoo style rendered as though drawn on vintage parchment.
# Instructions
- Produce a detailed scene description that includes every required subject, object, and stylistic cue.
- Preserve the intended Chicano tattoo-art sensibility: stylized, dramatic, expressive linework, monochrome palette, heavy stippling, and high-contrast shading.
- Ensure the composition feels balanc

Model Evaluation

Split data into random train and test subsets
  from sklearn.model_selection import train_test_split
  x_train, x_test, y_train, y_test = train_test_split(x_data, y_data, test_size=0.3, random_state=0)
    x_data: featrure or independent variables
    y_data dataset target: df['price']
    x_train, y_train: parts available data as training set
    x_test, y_test: parts of available data as testing set
    test_size: percentage of the data for testing(for here it's 30%)
    random_state: number g

neon

postgresql://pwdesignhtx:MKyzlQTm6n2a@ep-rapid-boat-a52fmjay-pooler.us-east-2.aws.neon.tech/neondb?sslmode=require&channel_binding=require

TRANSMISSION

{
  // ============================================================
  // Settings VS Code — poste corporate
  // Périmètre : core VS Code + GitHub Copilot uniquement.
  // Exclus : settings liés aux extensions tierces (Ruff, Pylance,
  // YAML, TOML, Terraform, Material Icons, Gemini) — à réintégrer
  // au fil des approbations du circuit d'allowlisting interne.
  // ============================================================

  // --- UI & Affichage (core) ---
  "window.zoomLevel": 0,
  "workb